Solutions to yesterday's starter
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Here’s my answer for today’s Maths Challenge.
I think that the way to make 83p with the fewest amount of coins would be to use a 50p+20p+10p+2p+1p=83p
To make £1.34 I would use a £1+20p+10+2p+2p=£1.34
For £5.27 I would use a £2+£2+£1+20p+5p+2p=£5.27
I think the smallest amount you can make with more than 5 coins is 6p (1p+1p+1p+1p+1p+1p=6p)
Here is my solution:
A) 83p = 50p + 20p + 10p + 2p + 1p (five coins)
B) £1.34 = £1 + 20p + 10p + 2p + 2p (five coins)
C) £5.27 = £2 + £2 + £1 + 20p + 5p +2p (six coins)
D) I think that it is £1.83, which contains six coins (£1 + 50p + 20p + 10p + 2p + 1p)